document.write( "Question 208072: a rectangle is 8 feet longer than it is wide and has an area of 2900 feet squared. What are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #157410 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+8 \n" ); document.write( "LW=2,900 \n" ); document.write( "W(W+8)=2,900 \n" ); document.write( "W^2+8W-2,900=0 \n" ); document.write( "(W-50)(W+58)=0 \n" ); document.write( "W-50=0 \n" ); document.write( "W=50 ANS. FOR THE WIDTH. \n" ); document.write( "L=50+8 \n" ); document.write( "L=58 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "50*58=2,900 \n" ); document.write( "2,900=2,900\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |