document.write( "Question 208013: Julie and Eric row their boat (at a constant speed) 45 miles downstream for 5 hours, helped by the current. Rowing at the same rate, the trip back against the current takes 9 hours. Find the rate of the current. please help \n" ); document.write( "
Algebra.Com's Answer #157407 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Julie and Eric row their boat (at a constant speed) 45 miles downstream for 5 \n" ); document.write( " hours, helped by the current. Rowing at the same rate, the trip back against \n" ); document.write( " the current takes 9 hours. Find the rate of the current. \n" ); document.write( ": \n" ); document.write( "Let s = speed of the boat in still water \n" ); document.write( "Let c = rate of the current \n" ); document.write( "Then \n" ); document.write( "(s-c) = speed upstream \n" ); document.write( "(s+c) = speed downstream \n" ); document.write( ": \n" ); document.write( "Write two distance equation, use elimination \n" ); document.write( "5(s+c) = 45 \n" ); document.write( "9(s-c) = 45 \n" ); document.write( "Simplify, divide 1st equation by 5, 2nd equation by 9; results \n" ); document.write( "s + c = 9 \n" ); document.write( "s - c = 5 \n" ); document.write( "-----------Subtraction eliminates s, find c \n" ); document.write( "2c = 4 \n" ); document.write( "c = 2 mph is the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( "Find s: \n" ); document.write( "s + 2 = 9 \n" ); document.write( "s = 9-2 \n" ); document.write( "s = 7 mph in still water \n" ); document.write( ": \n" ); document.write( "Check solution in original upstream equation: \n" ); document.write( "9(7-2) = 45 \n" ); document.write( " \n" ); document.write( " |