document.write( "Question 208065This question is from textbook modern college algebra
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document.write( ": If A,B and C work together on a job, it will take 1 and 1/3 hours. If only A and B work, it would take 1 and 5/7 hours, but if B and C work, it would take 2 and 2/5 hours. How long it would take each man, working alone to complete the job? \r
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document.write( "A and B working together can do a job in 6 hours. A become ill after 3 hours of working with B, and B finished the job, continuing to work alone in 8 hours. How long would it take each working alone to do the job? \n" );
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Algebra.Com's Answer #157394 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If A,B and C work together on a job, it will take 1 and 1/3 hours. If only A and B work, it would take 1 and 5/7 hours, but if B and C work, it would take 2 and 2/5 hours. How long it would take each man, working alone to complete the job? \n" ); document.write( ": \n" ); document.write( "Change 1 & 1/3 hrs to \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "Simplify the shared work equations \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "convert 1 & 5/7 hrs to \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply 1st equation by 3 and subtract the 2nd equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "---------------------eliminates A & B, find C \n" ); document.write( " \n" ); document.write( "12 = 2C \n" ); document.write( "C = 6 hrs alone \n" ); document.write( ": \n" ); document.write( "The 3rd equation we can use decimal: 2 & 2/5 hrs = 2.4 hrs \n" ); document.write( " \n" ); document.write( "Replace C with 6, find B \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ".6B = 2.4 \n" ); document.write( "B = \n" ); document.write( "B = 4 hrs alone \n" ); document.write( ": \n" ); document.write( "Find A, using the 2nd equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "4A = 12 \n" ); document.write( "A = 3 hrs alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the 1st equation using a calc \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "A and B working together can do a job in 6 hours. A become ill after 3 hours of working with B, and B finished the job, continuing to work alone in 8 hours. How long would it take each working alone to do the job? \n" ); document.write( ": \n" ); document.write( "Working the same together equation: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Working when one gets sick equation: (B works a total of 11 hrs) \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply the above equation by 3 and subtract the 1st equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-----------------------------eliminates A \n" ); document.write( "16B = 1 \n" ); document.write( "B = 16 hrs alone \n" ); document.write( ": \n" ); document.write( "Find A using the 1st equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "10A = 6 * 16 \n" ); document.write( "10A = 96 \n" ); document.write( "A = 9.6 hrs alone \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution on a calc using the \"sick equation\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |