document.write( "Question 208081: Hello! I have been working on this problem for the past 20 min P=13+45ln x represents the percentage of inbound email in the us that is considered spam, where x is the number of years after 2000. calculate to 6 decimals on each step when necessary. \r
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Algebra.Com's Answer #157393 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since \"x is the number of years after 2000\", this means that when the year is 2003, the value of x is x=3\r
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\n" ); document.write( "\n" ); document.write( "So simply plug in x=3 into \"P=13%2B45%2Aln%28x%29\" to get: \r
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\n" ); document.write( "\n" ); document.write( "\"P=13%2B45%2Aln%283%29=13%2B45%2A1.0986=13%2B49.437=62.437\"\r
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\n" ); document.write( "\n" ); document.write( "So when \"x=3\", \"P=62.437\". So the percentage of spam in 2003 is 62.437%
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