document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=208064>Question 208064</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1405802111/algebrahomeworkh>Longman mathemathics for IGCSE book1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Show that the area of an equilateral triangle of side 2x is x^2square3, given that tan 60 degrees=square 3\r<BR>\n" );
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document.write( "This question is from the chapter of trigonometry:Tangent ratios.<BR>\n" );
document.write( "Please help me to solve this problem. It is really urgent. I would be highly obliged if you solve my question. Solve it as soon as possible. Thankyou very much indeed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157390 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157390\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Show that the area of an equilateral triangle of side 2x is x^2square3, given that tan 60 degrees=square 3 <BR>\n" );
document.write( ".<BR>\n" );
document.write( "Draw a diagram, it'll help you identify what was given and what you need to do.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Remember, area of a triangle is (1/2)bh<BR>\n" );
document.write( "where<BR>\n" );
document.write( "b is base (given as 2x)<BR>\n" );
document.write( "h is height<BR>\n" );
document.write( ".<BR>\n" );
document.write( "So, we need the height.<BR>\n" );
document.write( "Since tan = opposite/adjacent<BR>\n" );
document.write( "our setup then:<BR>\n" );
document.write( "tan(60) = h/(2x/2) = h/x<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29+=+h%2Fx+ ALIGN=MIDDLE  ALT=\"sqrt%283%29+=+h%2Fx+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+sqrt%283%29+=+h+ ALIGN=MIDDLE  ALT=\"x+sqrt%283%29+=+h+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29bh ALIGN=MIDDLE  ALT=\"%281%2F2%29bh\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%292x%28x+sqrt%283%29%29 ALIGN=MIDDLE  ALT=\"%281%2F2%292x%28x+sqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"x%5E2%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );