document.write( "Question 208038: While finding the amount of seed needed to plant his 3 square wheat fields, Hank observed that the side of one field was 1 kilometer longer than the side of the smallest field and that the side of the largest field was 3 kilometers longer than the side of the smallest field. If the total area of the 3 fields is 38 square kilometers, then what is the area of each field? \n" ); document.write( "
Algebra.Com's Answer #157351 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = side of smallest field
\n" ); document.write( "x+1= side of second field
\n" ); document.write( "x+3 = side of third field\r
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\n" ); document.write( "\n" ); document.write( "Area = x^2 + (x+1)^2 + (x+3)^2 = 38\r
\n" ); document.write( "\n" ); document.write( "x^2 + x^2 + 2x + 1 + x^2 + 6x + 9 = 38
\n" ); document.write( "3x^2 + 8x +10 = 38\r
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\n" ); document.write( "\n" ); document.write( "3x^2 + 8x -28=0
\n" ); document.write( "(3x+14)(x-2)=0\r
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\n" ); document.write( "\n" ); document.write( "Two solutions:
\n" ); document.write( "3x+14 = 0
\n" ); document.write( "3x= -14
\n" ); document.write( "x=-14/3 Reject negative answers\r
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\n" ); document.write( "\n" ); document.write( "x-2=0
\n" ); document.write( "x=2
\n" ); document.write( "A=4 km^2\r
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\n" ); document.write( "\n" ); document.write( "x+1=3
\n" ); document.write( "A=9 km^2\r
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\n" ); document.write( "\n" ); document.write( "x+3= 5
\n" ); document.write( "A= 25 km^2\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "Total area = 4 + 9 + 25= 38 km^2\r
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\n" ); document.write( "\n" ); document.write( "R^2\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
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