document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=207993>Question 207993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I tried the figuring with y = 0 and have do not think this is correct. Now I am clueless as to how to approach this problem.Point A (-4,1) is in the standard x, y coordinate plane. What must be the coordinates of point B so that the line x = 2 is the perpendicular bisector of AB? Thank you for your help.I have an exam in 2 days! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157350 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=2 is a vertical line (y is not defined and so can have any value)\r<BR>\n" );
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document.write( "the perpendicular line must be horizontal and of the form y=?\r<BR>\n" );
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document.write( "this means A and B have the same y-coordinate (1)\r<BR>\n" );
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document.write( "x=2 is the bisector of AB so the distance from A to x=2 is the same as the distance from x=2 to B<BR>\n" );
document.write( "___ 2 - -4 = ? - 2 ___ 6 = 8 - 2 ___ so the x-coordinate of B is 8\r<BR>\n" );
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document.write( "point B is (8,1) </SPAN>\n" );
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