document.write( "Question 208034: Suppose you are offered two jobs. One pays $30,000 the first year with annual raises of $2000 each year. The second offers a starting salary of $27,000 and raises of 8% each year. At the end of ten years, what would your yearly salary be from a) the first job? b)the second job?
\n" ); document.write( "My answer; $30,000=1 year + $2000=each coming year * 10 years
\n" ); document.write( "but since the first year is already given I dont have to count it with do I? (thats why I am not sure if I got this right)
\n" ); document.write( "a) 2000*9=18,000 30,000+18,000=48,000 so $48,000 after 10 years
\n" ); document.write( "b)27,000=1 year + 8% each coming year * 10 years
\n" ); document.write( "(here again I only put 9 years to count, since 27,000 already is the first year, or is that wrong?)
\n" ); document.write( "270*8=2,160 2,160*9=19,440 27,000+19,440=46,440 so $46,440 after 10 years
\n" ); document.write( "Could someone please tell me if I solved the problem right?
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Algebra.Com's Answer #157344 by Theo(13342)\"\" \"About 
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Suppose you are offered two jobs. One pays $30,000 the first year with annual raises of $2000 each year. The second offers a starting salary of $27,000 and raises of 8% each year. At the end of ten years, what would your yearly salary be from a) the first job? b)the second job?
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\n" ); document.write( "If we assume that the salary increase is at the end of each year, we get the following:
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\n" ); document.write( "first job would be $30,000 + (10 * $2,000) = $50,000
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\n" ); document.write( "second job would be $27,000 * (1.08)^10 = $58,290.97
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\n" ); document.write( "If we assume that the salary increase is at the beginning of each year, we get the following:
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\n" ); document.write( "first job would be $30,000 + (9 * $2,000) = $48,000
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\n" ); document.write( "second job would be $27,000 * (1.08)^9 = $53,973.12
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\n" ); document.write( "It doesn't really matter whether you used 9 years or 10 years
\n" ); document.write( "because you will be making more money at the second job either way.
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\n" ); document.write( "They are asking:
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\n" ); document.write( "At the end of ten years, what would your yearly salary be from a) the first job? b)the second job?
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\n" ); document.write( "This is nebulous and clearly open to interpretation. They do not clearly state when you get the annual salary increase.
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\n" ); document.write( "In a real world situation you would have had to ask for a clarification as to they wanted you to make the calculations.
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\n" ); document.write( "your answer should include:
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\n" ); document.write( "if they get a raise at the end of each year, then at the end of the 10th year the annual salary would be.
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\n" ); document.write( "your alternate answer should include:
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\n" ); document.write( "if they get a raise at the beginning of the next year, then at the end of the 10th year, the annual salary would be.
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\n" ); document.write( "in the first case, carrying out the operations 10 years would be correct.
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\n" ); document.write( "in the alternate case, carrying out the operations 9 years would be correct.
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\n" ); document.write( "when you do the 8% solution, you are doing compound interest, not simple interest.
\n" ); document.write( "simple interest would be $27,000 + (.08*10*27000)
\n" ); document.write( "compound interest would be $27,000 * (1.08)^10 as shown.
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\n" ); document.write( "first proposal yearly salary with raises at the end of each year would look like this.
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\n" ); document.write( "end of year 1: $32,000
\n" ); document.write( "end of year 2: $34,000
\n" ); document.write( "end of year 3: $36,000
\n" ); document.write( "end of year 4: $38,000
\n" ); document.write( "end of year 5: $40,000
\n" ); document.write( "end of year 6: $42,000
\n" ); document.write( "end of year 7: $44,000
\n" ); document.write( "end of year 8: $46,000
\n" ); document.write( "end of year 9: $48,000
\n" ); document.write( "end of year 10: $50,000
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\n" ); document.write( "first proposal yearly salary with raises at the end of each year would look like this.
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\n" ); document.write( "end of year 1: $30,000
\n" ); document.write( "end of year 2: $32,000
\n" ); document.write( "end of year 3: $34,000
\n" ); document.write( "end of year 4: $36,000
\n" ); document.write( "end of year 5: $38,000
\n" ); document.write( "end of year 6: $40,000
\n" ); document.write( "end of year 7: $42,000
\n" ); document.write( "end of year 8: $44,000
\n" ); document.write( "end of year 9: $46,000
\n" ); document.write( "end of year 10: $48,000
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\n" ); document.write( "he doesn't get $50,000 until the beginning of the 11th year.
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\n" ); document.write( "same concept applies for the 8% case.
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\n" ); document.write( "Without knowing, you need to qualify your answer as I indicated and I would think you need to show both answers with the qualification for each.
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\n" ); document.write( "My answer would be:
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\n" ); document.write( "If the salary increases at the end of each year, then:
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\n" ); document.write( "first job would be paying $30,000 + (10 * $2,000) = $50,000 and the second job would be $27,000 * (1.08)^10 = $58,290.97
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\n" ); document.write( "If the salary increases at the beginning of each year, then:
\n" ); document.write( "-----
\n" ); document.write( "first job would be paying $30,000 + (9 * $2,000) = $48,000 and the second job would be $27,000 * (1.08)^9 = $53,973.12
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