document.write( "Question 208023: please help me how to solve this. because i can't get it.\r
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document.write( "1) the width of the rectangle is one-forth of its lenght. if the perimeter is 40 cm, find the dimensions of the rectangles?\r
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document.write( "2) the perimeter of a standard basketball court is 288ft. find the dimensions of the basketball court if its lenght is 44ft longer than its width. \n" );
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Algebra.Com's Answer #157340 by Theo(13342)![]() ![]() You can put this solution on YOUR website! ----- \n" ); document.write( "PROBLEM 1 \n" ); document.write( "----- \n" ); document.write( "1) the width of the rectangle is one-forth of its lenght. if the perimeter is 40 cm, find the dimensions of the rectangles? \n" ); document.write( "----- \n" ); document.write( "let W = width \n" ); document.write( "let L = length \n" ); document.write( "L = (4 * W) which is the same as (W = L / 4) \n" ); document.write( "P = 40 \n" ); document.write( "= (2 * L) + (2 * W) \n" ); document.write( "= (2 * (4 * W)) + (2 * W) after replacing L with 4*W \n" ); document.write( "= (8 * W) + (2 * W) \n" ); document.write( "= (10 * W) \n" ); document.write( "----- \n" ); document.write( "40 = (10 * W) \n" ); document.write( "W = (40 / 10) = 4 after dividing both sides of the equation by 10. \n" ); document.write( "----- \n" ); document.write( "so far you have W = 4 \n" ); document.write( "----- \n" ); document.write( "L = (4 * W) = (4 * 4) = 16 \n" ); document.write( "----- \n" ); document.write( "now you also have L = 16 \n" ); document.write( "----- \n" ); document.write( "W = 4 \n" ); document.write( "L = 16 \n" ); document.write( "W = (L / 4) = (16 / 4) = 4 = correct based on the problem statement. \n" ); document.write( "----- \n" ); document.write( "(2 * L) + (2 * W) = 40 \n" ); document.write( "= (2 * 16) + (2 * 4) = 40 \n" ); document.write( "= (32 + 8) = 40 \n" ); document.write( "40 = 40 = correct with W = 4 and L = 16. \n" ); document.write( "----- \n" ); document.write( "your answer is: \n" ); document.write( "the width of the rectangle is 4 and the length of the rectangle is 16. \n" ); document.write( "----- \n" ); document.write( "PROBLEM 2 \n" ); document.write( "----- \n" ); document.write( "2) the perimeter of a standard basketball court is 288ft. find the dimensions of the basketball court if its lenght is 44ft longer than its width. \n" ); document.write( "----- \n" ); document.write( "P = 288 feet. \n" ); document.write( "L = (W + 44) \n" ); document.write( "(2 * L) + (2 * W) = 288 \n" ); document.write( "= (2 * (W + 44)) + (2 * W) = 288 after replacing L with W + 44. \n" ); document.write( "= (2 * W) + (2 * 44) + (2 * W) = 288 \n" ); document.write( "= (4 * W) + 88 = 288 \n" ); document.write( "= (4 * W) = 200 \n" ); document.write( "= W = (200 / 4) = 50 after dividing both sides of the equation by 4. \n" ); document.write( "----- \n" ); document.write( "so far you have W = 50 \n" ); document.write( "----- \n" ); document.write( "L = (W + 44) = (50 + 44) = 94 \n" ); document.write( "----- \n" ); document.write( "now you also have L = 94 \n" ); document.write( "----- \n" ); document.write( "(2 * L) + (2 * W) = 288 \n" ); document.write( "(2 * 94) + (2 * 50) = 288 \n" ); document.write( "(188 + 100) = 288 = correct based on W = 50 and L = 94. \n" ); document.write( "----- \n" ); document.write( "your answer is: \n" ); document.write( "length = 94 feet \n" ); document.write( "width = 50 feet \n" ); document.write( " |