document.write( "Question 207968: I have four problems to use this with if you could help me with one it would be great thanks.An operation $ has been defined over the set of natural numbers. in each case, find 2$3, determine whether or not the set of natural numbers is closed under $, determine if $ is commutative and determine if is associative.\r
\n" ); document.write( "\n" ); document.write( "x$y=(1+x)+y
\n" ); document.write( "

Algebra.Com's Answer #157314 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
An operation $ has been defined over the set of natural numbers. in each case, find 2$3, determine whether or not the set of natural numbers is closed under $, determine if $ is commutative and determine if is associative.
\n" ); document.write( "----------------------------
\n" ); document.write( "x$y=(1+x)+y
\n" ); document.write( "Then 2$3 = (1+2)+3 = 6
\n" ); document.write( "------------------------------------
\n" ); document.write( "Naturals closed under $ ?
\n" ); document.write( "Let a and b be natural numbers
\n" ); document.write( "Then a$b = (1+a)+b = 1+(a+b)
\n" ); document.write( "Since the natural numbers are closed under addition,
\n" ); document.write( "1 + (a+b) is is a natural number. So the set of
\n" ); document.write( "natural numbers is closed under $.
\n" ); document.write( "------------------------------------
\n" ); document.write( "Is # communtative?
\n" ); document.write( "Show that a$b = b$a
\n" ); document.write( "(1+a)+b = (1+b)+a
\n" ); document.write( "1 + a + b = 1+ b + a
\n" ); document.write( "Since the naturals are commutative,
\n" ); document.write( "1 + a + b = 1 + a+b
\n" ); document.write( "--------------------------
\n" ); document.write( "Is $ associative?
\n" ); document.write( "Show that (a$b)$c = a$(b$c)
\n" ); document.write( "============
\n" ); document.write( "Can you do that?
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );