document.write( "Question 207968: I have four problems to use this with if you could help me with one it would be great thanks.An operation $ has been defined over the set of natural numbers. in each case, find 2$3, determine whether or not the set of natural numbers is closed under $, determine if $ is commutative and determine if is associative.\r
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document.write( "x$y=(1+x)+y \n" );
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Algebra.Com's Answer #157314 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An operation $ has been defined over the set of natural numbers. in each case, find 2$3, determine whether or not the set of natural numbers is closed under $, determine if $ is commutative and determine if is associative. \n" ); document.write( "---------------------------- \n" ); document.write( "x$y=(1+x)+y \n" ); document.write( "Then 2$3 = (1+2)+3 = 6 \n" ); document.write( "------------------------------------ \n" ); document.write( "Naturals closed under $ ? \n" ); document.write( "Let a and b be natural numbers \n" ); document.write( "Then a$b = (1+a)+b = 1+(a+b) \n" ); document.write( "Since the natural numbers are closed under addition, \n" ); document.write( "1 + (a+b) is is a natural number. So the set of \n" ); document.write( "natural numbers is closed under $. \n" ); document.write( "------------------------------------ \n" ); document.write( "Is # communtative? \n" ); document.write( "Show that a$b = b$a \n" ); document.write( "(1+a)+b = (1+b)+a \n" ); document.write( "1 + a + b = 1+ b + a \n" ); document.write( "Since the naturals are commutative, \n" ); document.write( "1 + a + b = 1 + a+b \n" ); document.write( "-------------------------- \n" ); document.write( "Is $ associative? \n" ); document.write( "Show that (a$b)$c = a$(b$c) \n" ); document.write( "============ \n" ); document.write( "Can you do that? \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |