document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28819>Question 28819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is one hundred fifteen.  The second number is three times the first number.  The third number is two less than five times the first number.  Find the three numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15731 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the numbers be x,y,z<BR>\n" );
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document.write( "then x+y+z=115 (given)<BR>\n" );
document.write( "also y=3x (given)<BR>\n" );
document.write( "also z=(5x-2) (given)<BR>\n" );
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document.write( "x+y+z=115<BR>\n" );
document.write( "x+3x+(5x-2)=115<BR>\n" );
document.write( "9x=115+2<BR>\n" );
document.write( "x=117/9=13<BR>\n" );
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document.write( "x=13<BR>\n" );
document.write( "y=3x=39<BR>\n" );
document.write( "z=5x-2=65-2=63<BR>\n" );
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document.write( "13,39,63<BR>\n" );
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document.write( "Prabhat </SPAN>\n" );
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