document.write( "Question 207940: how much 20% antifreeze solution must be mixed with a 40% antifreeze solution to produce 25 gallons of a 32% disinfectant solution? round to the nearest gallon.
\n" ); document.write( "? gallons 20% solution, ? gallons 40% solution
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Algebra.Com's Answer #157295 by checkley77(12844)\"\" \"About 
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.40x+.20(25-x)=.32*25
\n" ); document.write( ".40x+5-.20x=8
\n" ); document.write( ".20x=8-5
\n" ); document.write( ".20x=3
\n" ); document.write( "x=3/-20
\n" ); document.write( "x=15 gal. of 40% is used.
\n" ); document.write( "25-15=10 gal. of 20% is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".40*15+.20*10=8
\n" ); document.write( "6+2=8
\n" ); document.write( "8=8
\n" ); document.write( "10 gallons 20% solution, 15 gallons 40% solution
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