document.write( "Question 207940: how much 20% antifreeze solution must be mixed with a 40% antifreeze solution to produce 25 gallons of a 32% disinfectant solution? round to the nearest gallon.
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document.write( "? gallons 20% solution, ? gallons 40% solution \n" );
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Algebra.Com's Answer #157295 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .40x+.20(25-x)=.32*25 \n" ); document.write( ".40x+5-.20x=8 \n" ); document.write( ".20x=8-5 \n" ); document.write( ".20x=3 \n" ); document.write( "x=3/-20 \n" ); document.write( "x=15 gal. of 40% is used. \n" ); document.write( "25-15=10 gal. of 20% is used. \n" ); document.write( "Proof: \n" ); document.write( ".40*15+.20*10=8 \n" ); document.write( "6+2=8 \n" ); document.write( "8=8 \n" ); document.write( "10 gallons 20% solution, 15 gallons 40% solution \n" ); document.write( " |