document.write( "Question 207886: My motor boat normally travels at 24 km/h in still water. One day I travelled 36 km against a constant current in a river and it took me the same time to travel 48 km with the current. How fast was the current? \n" ); document.write( "
Algebra.Com's Answer #157246 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
The basic formula is d=rt, and since the equation is based upon the fact that time up stream is equal to time downstream, it will be helpful to solve for t.\r
\n" ); document.write( "\n" ); document.write( "\"t=d%2Fr\"\r
\n" ); document.write( "\n" ); document.write( "Let x = rate of current.
\n" ); document.write( "24 = rate in still water \r
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\n" ); document.write( "\n" ); document.write( "24+x = rate downstream
\n" ); document.write( "24-x = rate upstream\r
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\n" ); document.write( "\n" ); document.write( "time downstream = \"d%2Fr=48%2F%2824%2Bx%29\"
\n" ); document.write( "time upstream = \"d%2Fr=36%2F%2824-x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the equation: \"48%2F%2824%2Bx%29+=+36%2F%2824-x%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"a%2Fb=c%2Fd\" means that \"ad=bc\",
\n" ); document.write( "\"48%2F%2824%2Bx%29+=+36%2F%2824-x%29+\" means that \"48%2824-x%29+=+36%2824%2Bx%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Get out your calculator:
\n" ); document.write( "\"1156+-48x+=+864%2B36x\"
\n" ); document.write( "\"1152-864+=+48x+%2B36x\"
\n" ); document.write( "\"288=84x\"
\n" ); document.write( "\"x=288%2F84=24%2F7+\" km/h\r
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\n" ); document.write( "\n" ); document.write( "R^2\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje
\n" ); document.write( "Altamonte Springs Campus
\n" ); document.write( "Seminole State University
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