document.write( "Question 207886: My motor boat normally travels at 24 km/h in still water. One day I travelled 36 km against a constant current in a river and it took me the same time to travel 48 km with the current. How fast was the current? \n" ); document.write( "
Algebra.Com's Answer #157246 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! The basic formula is d=rt, and since the equation is based upon the fact that time up stream is equal to time downstream, it will be helpful to solve for t.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x = rate of current. \n" ); document.write( "24 = rate in still water \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "24+x = rate downstream \n" ); document.write( "24-x = rate upstream\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "time downstream = \n" ); document.write( "time upstream = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve the equation: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Get out your calculator: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje \n" ); document.write( "Altamonte Springs Campus \n" ); document.write( "Seminole State University \n" ); document.write( " |