document.write( "Question 207887: A rectangular deck has an area of (x2 + 6x + 8) square feet. If its width is (x + 2) feet then:\r
\n" ); document.write( "\n" ); document.write( "a. Find its length in terms of ‘x’.
\n" ); document.write( "b. If x = 3, what will be the area, length and width in feet. \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #157243 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
x^2 + 6x +8 just happens to factor into (x+2)(x+4)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So, if x+2 is the width, then x+4 must be the length.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If x=3, then the width is x+2, which is 5 feet, the length is x+4, which is 7 feet, and the area is the product 5*7 which is 35 square feet.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2
\n" ); document.write( "
\n" );