document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28824>Question 28824</A>: <I><SPAN STYLE=\"word-break: break-all;\">    Goodevening!!! I have the new problems again and i beg you to answer me more clearly. <BR>\n" );
document.write( "        I can not solve (1) 4x - y = -3 and 2x -3y = 1<BR>\n" );
document.write( "                        (2) 2x + 4y = -12 and 3x + 5y = -14<BR>\n" );
document.write( "                        (3) 2x - 3y = 2 and -4x + 6y = 2<BR>\n" );
document.write( "                                <BR>\n" );
document.write( "                                     how to solve ?? <BR>\n" );
document.write( "                                      <BR>\n" );
document.write( "                                         Your Faithfully <BR>\n" );
document.write( "                                             student E'mmaModi </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15724 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1) 4x - y = -3 and 2x -3y = 1<BR>\n" );
document.write( "<TABLE  BORDER=1>\n" );
document.write( "\n" );
document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear_substitution.solver>SOLVE linear system by SUBSTITUTION</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++4%5Cx+%2B+-1%5Cy+=+-3%2C%0D%0A++++2%5Cx+%2B+-3%5Cy+=+1+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++4%5Cx+%2B+-1%5Cy+=+-3%2C%0D%0A++++2%5Cx+%2B+-3%5Cy+=+1+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" >We'll use substitution. After moving -1*y to the right, we get:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Ax+=+-3+-+-1%2Ay ALIGN=MIDDLE  ALT=\"4%2Ax+=+-3+-+-1%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-3%2F4+-+-1%2Ay%2F4 ALIGN=MIDDLE  ALT=\"x+=+-3%2F4+-+-1%2Ay%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Substitute that<BR>\n" );
document.write( "  into another equation:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A%28-3%2F4+-+-1%2Ay%2F4%29+%2B+-3%5Cy+=+1 ALIGN=MIDDLE  ALT=\"2%2A%28-3%2F4+-+-1%2Ay%2F4%29+%2B+-3%5Cy+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > and simplify: So, we know that y=-1. Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-3%2F4+-+-1%2Ay%2F4 ALIGN=MIDDLE  ALT=\"x+=+-3%2F4+-+-1%2Ay%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >, x=-1.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28+x=-1%2C+y=-1+%29 ALIGN=MIDDLE  ALT=\"system%28+x=-1%2C+y=-1+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "  </TD></TR>\n" );
document.write( "</TABLE><BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(2) 2x + 4y = -12 and 3x + 5y = -14<BR>\n" );
document.write( "<TABLE  BORDER=1>\n" );
document.write( "\n" );
document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear_substitution.solver>SOLVE linear system by SUBSTITUTION</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++2%5Cx+%2B+4%5Cy+=+-12%2C%0D%0A++++3%5Cx+%2B+5%5Cy+=+-14+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++2%5Cx+%2B+4%5Cy+=+-12%2C%0D%0A++++3%5Cx+%2B+5%5Cy+=+-14+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" >We'll use substitution. After moving 4*y to the right, we get:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Ax+=+-12+-+4%2Ay ALIGN=MIDDLE  ALT=\"2%2Ax+=+-12+-+4%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-12%2F2+-+4%2Ay%2F2 ALIGN=MIDDLE  ALT=\"x+=+-12%2F2+-+4%2Ay%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Substitute that<BR>\n" );
document.write( "  into another equation:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A%28-12%2F2+-+4%2Ay%2F2%29+%2B+5%5Cy+=+-14 ALIGN=MIDDLE  ALT=\"3%2A%28-12%2F2+-+4%2Ay%2F2%29+%2B+5%5Cy+=+-14\"   DISABLED_style= \"max-width:90%; height:auto;\" > and simplify: So, we know that y=-4. Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-12%2F2+-+4%2Ay%2F2 ALIGN=MIDDLE  ALT=\"x+=+-12%2F2+-+4%2Ay%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, x=2.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28+x=2%2C+y=-4+%29 ALIGN=MIDDLE  ALT=\"system%28+x=2%2C+y=-4+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "  </TD></TR>\n" );
document.write( "</TABLE><BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(3) 2x - 3y = 2 and -4x + 6y = 2<BR>\n" );
document.write( "<TABLE  BORDER=1>\n" );
document.write( "\n" );
document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear_substitution.solver>SOLVE linear system by SUBSTITUTION</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++2%5Cx+%2B+-3%5Cy+=+2%2C%0D%0A++++-4%5Cx+%2B+6%5Cy+=+2+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++2%5Cx+%2B+-3%5Cy+=+2%2C%0D%0A++++-4%5Cx+%2B+6%5Cy+=+2+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" >We'll use substitution. After moving -3*y to the right, we get:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Ax+=+2+-+-3%2Ay ALIGN=MIDDLE  ALT=\"2%2Ax+=+2+-+-3%2Ay\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2%2F2+-+-3%2Ay%2F2 ALIGN=MIDDLE  ALT=\"x+=+2%2F2+-+-3%2Ay%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Substitute that<BR>\n" );
document.write( "  into another equation:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4%2A%282%2F2+-+-3%2Ay%2F2%29+%2B+6%5Cy+=+2 ALIGN=MIDDLE  ALT=\"-4%2A%282%2F2+-+-3%2Ay%2F2%29+%2B+6%5Cy+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and simplify: So, we know that y=-6=0. Since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2%2F2+-+-3%2Ay%2F2 ALIGN=MIDDLE  ALT=\"x+=+2%2F2+-+-3%2Ay%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, x=-8.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28+x=-8%2C+y=-6=0+%29 ALIGN=MIDDLE  ALT=\"system%28+x=-8%2C+y=-6=0+%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "  </TD></TR>\n" );
document.write( "</TABLE><BR>\n" );
document.write( "\n" );
document.write( "<br><BR>\n" );
document.write( "xC </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );