document.write( "Question 207844: i do not know what to do on this problem.
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document.write( "How much 40% antifreeze solution must be mixed with a 80% antifreeze solution to produce 20 gallons of a 70% disinfectant solution? Round answer to the nearest gallon.
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document.write( "? gallons 40% solution, ? gallons 80% solution \n" );
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Algebra.Com's Answer #157203 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .40x+.80(20-x)=.70*20 \n" ); document.write( ".40x+16-.80x=14 \n" ); document.write( "-.40x=14-16 \n" ); document.write( "-.40x=-2 \n" ); document.write( "x=-2/.40 \n" ); document.write( "x=5 gal of 40% antifreeze is used. \n" ); document.write( "20-5=15 gal of 80% anti freeze is used. \n" ); document.write( "[5] gallons 40% solution, [15] gallons 80% solution \n" ); document.write( "Proof: \n" ); document.write( ".4*5+.8*15=.7*20 \n" ); document.write( "2+12=14 \n" ); document.write( "14=14 \n" ); document.write( " |