document.write( "Question 207844: i do not know what to do on this problem.
\n" ); document.write( "How much 40% antifreeze solution must be mixed with a 80% antifreeze solution to produce 20 gallons of a 70% disinfectant solution? Round answer to the nearest gallon.
\n" ); document.write( "? gallons 40% solution, ? gallons 80% solution
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Algebra.Com's Answer #157203 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.40x+.80(20-x)=.70*20
\n" ); document.write( ".40x+16-.80x=14
\n" ); document.write( "-.40x=14-16
\n" ); document.write( "-.40x=-2
\n" ); document.write( "x=-2/.40
\n" ); document.write( "x=5 gal of 40% antifreeze is used.
\n" ); document.write( "20-5=15 gal of 80% anti freeze is used.
\n" ); document.write( "[5] gallons 40% solution, [15] gallons 80% solution
\n" ); document.write( "Proof:
\n" ); document.write( ".4*5+.8*15=.7*20
\n" ); document.write( "2+12=14
\n" ); document.write( "14=14
\n" ); document.write( "
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