document.write( "Question 28750: 9x^2+30x+25=11
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Algebra.Com's Answer #15716 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! 9x^2+30x+25=11 \n" ); document.write( "9x^2+30x+25-11=0 \n" ); document.write( "9x^2+30x+14=0 ----(1) \n" ); document.write( "Given ax^2 +bx +c = 0, by formula x = [(-b)+ orminus sqrt(b^2-4ac)]/2a \n" ); document.write( "Here a=9, b=30 and c-14 \n" ); document.write( "x= [(-30)+or minus sqrt(30^2-4X9X14)]/(2X9) \n" ); document.write( "= [(-30)+or minus sqrt(900-504)]/(18) \n" ); document.write( "= [(-30)+or minus sqrt(396)]/(18) \n" ); document.write( "= [(-30)+or minus sqrt(36X11)]/(18) \n" ); document.write( "= [(-30)+or minus 6sqrt(11)]/(18) \n" ); document.write( "= [-5+orminus rt(11)]/3 (cancelling 6 in the nr and in the dr) \n" ); document.write( "Therefore \n" ); document.write( "x= (-5+sqrt(11)]/3 or x= (-5-sqrt(11)]/3 \n" ); document.write( "Verification: Putting x=(-5+sqrt(11)]/3 in (1) \n" ); document.write( "LHS = 9x^2+30x+14 \n" ); document.write( "= [-5+rt(11)]^2+10[-5+rt(11)]+14 \n" ); document.write( "=(-5)^2+ (rt(11))^2-10rt(11)-50+10rt(11)+14 \n" ); document.write( "=25+11-50+14 \n" ); document.write( "=50-50=0 \n" ); document.write( "=RHS \n" ); document.write( "Note: Since quadratic surds occur in conjuagate pairs \n" ); document.write( "the other value also must hold\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |