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HOW DO U DO THIS y=3x + 9 when u are trying to figure out the x and y intercept\r
\n" ); document.write( "\n" ); document.write( "Given the general form of equation
\n" ); document.write( "Ax+By+C= 0----(1)
\n" ); document.write( "How to represent it in the intercept form? is the problem on hand. Right?
\n" ); document.write( "The procedure for throwing a given equation to a line in the general form to its intercept form is as follows:
\n" ); document.write( "Retain the x and y part on one side and take the constant to the other side.
\n" ); document.write( "Ax+By = -C
\n" ); document.write( "Divide through out by the constant on the other side so as to get 1 as our constant on that other side.
\n" ); document.write( "[A/(-C)]x+[B/(-C)]y = 1
\n" ); document.write( "Inorder to make the coefficient of x and y 1 in the nr,write the above as
\n" ); document.write( "[1/(-C)/A]x +[1/(-C)/B]y = 1
\n" ); document.write( "That is x/[(-C)/A]+y/[(-C)/B] = 1
\n" ); document.write( "Now the line is in the standard intercept form
\n" ); document.write( "x/a+y/b = 1
\n" ); document.write( "where the the x-intercept = a and the y-intercept = b
\n" ); document.write( "In the above illustration,the x-intercept = (-C)/A and the y-intercept = (-C)/B\r
\n" ); document.write( "\n" ); document.write( "Let us consider two examples one with constant on the LHS negative and the other with the constant on the LHS positive in the general form Ax+By+C=0\r
\n" ); document.write( "\n" ); document.write( "1)2x+5y-3 = 0 ----(I)
\n" ); document.write( "2x+5y = 3
\n" ); document.write( "(2/3)x+(5/3)y =1
\n" ); document.write( "x/(3/2)+y/(3/5) = 1
\n" ); document.write( "Therefore x-intercept = (3/2) and y-intercept = (3/5)
\n" ); document.write( "2)3x+7y+15 = 0 ----(II)
\n" ); document.write( " 3x +7y =-15
\n" ); document.write( "[3/(-15)]x+ [7/(-15)]y =1
\n" ); document.write( "x/[(-15)/3]+ y/[(-15)/7]=1
\n" ); document.write( "Therefore x-intercept = (-15/3)=-5 and y-intercept = (-15/7)\r
\n" ); document.write( "\n" ); document.write( "Coming to your problem
\n" ); document.write( "y=3x + 9 which is
\n" ); document.write( "3x-y = -9----(1)
\n" ); document.write( "(actually the general form is 3x-y+9=0, the C illustrated above is actually 9)
\n" ); document.write( "(Got it!. The x and y part are on one side
\n" ); document.write( "and the costant part on the other side)
\n" ); document.write( "Dividing by (-9) through out
\n" ); document.write( "[3/(-9)]x +[(-1)/(-9)]y = 1
\n" ); document.write( "[1/(-3)}x +[1/9]y = 1
\n" ); document.write( "x/(-3)+y/9 = 1
\n" ); document.write( "Therefore x-intercept = (-3) and y - intercept = 9
\n" ); document.write( "Verification: Consider the intercept form that we have got.
\n" ); document.write( "x/(-3)+y/9 = 1
\n" ); document.write( "Multiplying through out by 9,
\n" ); document.write( "-3x+y =9
\n" ); document.write( "That is y = 3x+9 (adding +3x to both the sides)
\n" ); document.write( "Note: After throwing the given equation in the x/a+y/b = 1 form,
\n" ); document.write( "the dr under x gives the x-intercept(along with the sign) and
\n" ); document.write( "the dr under y gives the y-intercept(along with the sign) \r
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