document.write( "Question 207744This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": The width of a rectangle gate is 2 meters larger than its height. The diagonal breace measures (sqrt 6 meters). Find the width and the height.
\n" ); document.write( "I'm lost. I think I need to set it up as a^2 + b^2 = c^2, I'm not sure...but I still don't know where to go from there. Please help!! \n" ); document.write( "
Algebra.Com's Answer #157132 by nerdybill(7384)\"\" \"About 
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The width of a rectangle gate is 2 meters larger than its height. The diagonal breace measures (sqrt 6 meters). Find the width and the height.
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\n" ); document.write( "You need to apply Pythagorean theorem:
\n" ); document.write( "Let h = height
\n" ); document.write( "then
\n" ); document.write( "h+2 = width
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\n" ); document.write( "h^2 + (h+2)^2 = 6^2
\n" ); document.write( "h^2 + (h+2)(h+2) = 36
\n" ); document.write( "h^2 + (h^2+4h+4) = 36
\n" ); document.write( "2h^2+4h+4 = 36
\n" ); document.write( "h^2+2h+2 = 18
\n" ); document.write( "h^2+2h-16 = 0
\n" ); document.write( "(h+8)(h-2) = 0
\n" ); document.write( "h = {-8,2}
\n" ); document.write( "We can toss out the negative solution leaving:
\n" ); document.write( "h = 2 meters (height)
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\n" ); document.write( "h+2 = 2+2 = 3 meters (width) \n" ); document.write( "
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