document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=207733>Question 207733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dear sir or mam:<BR>\n" );
document.write( "I am working on factoring trinomials completely<BR>\n" );
document.write( "16x^2-104x+169 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157122 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16x^2 -104x +169<BR>\n" );
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document.write( "factors  of  16:,,1-16,,2-8,,4-4,,,,,factors  of  169:,,1-169,,,,13-13<BR>\n" );
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document.write( "last  term  is  +,,,,therefore sum  of  inside,outside  terms = 104,,,<BR>\n" );
document.write( "and,,,as  middle  term  is  -,,,both  signs  are  negative<BR>\n" );
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document.write( "(4x-13)(4x-13)<BR>\n" );
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document.write( "check  using  FOIL,<BR>\n" );
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document.write( "4x^2 -52x -52x +169,,  4x^2 -104x +169,,,,ok<BR>\n" );
document.write( ". </SPAN>\n" );
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