document.write( "Question 207652: hello tutors. i need your help with this problem. \r
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document.write( "find an equation of the line that passes through the origin and the point (4,-8)\r
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document.write( "thank you so much, my memory is very rusty and i could really use a refresher! \n" );
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Algebra.Com's Answer #157050 by Theo(13342)![]() ![]() You can put this solution on YOUR website! equation of straight line is y = mx + b where m is the slope and b is the y intercept. \n" ); document.write( "----- \n" ); document.write( "if the line passes through the origin, then 1 point on the line is (0,0) and the other point is (4,-8) as given. \n" ); document.write( "----- \n" ); document.write( "slope is (y2-y1)/(x2-x1) \n" ); document.write( "if we let (x1,y1) = (0,0) and we let (x2,y2) = (4,-8), then the slope equation becomes \n" ); document.write( "(-8-0)/(4-0) = (-8)/(4) = -2. \n" ); document.write( "----- \n" ); document.write( "to solve for the y intercept we can use either point and substitute it in the equation of y = -2*x + b \n" ); document.write( "----- \n" ); document.write( "assuming (0,0) is the point, that equation becomes 0 = -2*0 + b making b = 0 \n" ); document.write( "----- \n" ); document.write( "assuming (4,-8) is the point, that equation becomes -8 = -2*4 + b which becomes -8 = -8 * b which becomes b = 0 once we add 8 to both sides of the equation. \n" ); document.write( "----- \n" ); document.write( "the equation of your line should be y = 2*x \n" ); document.write( "----- \n" ); document.write( "a graph of your equation will look like this. \n" ); document.write( "when x is 0, y is 0. \n" ); document.write( "when x is 1, y is -2. \n" ); document.write( "when x is 2, y is -4. \n" ); document.write( "when x is -1, y is 2. \n" ); document.write( "when x is 2, y is 4. \n" ); document.write( "etc., as shown on the graph. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |