document.write( "Question 207647This question is from textbook
\n" ); document.write( ": Find the vertical asymptotes of F(x)= (3x+5)/(6x^2-x-2). \r
\n" ); document.write( "\n" ); document.write( "Would this problem be x=1/2, x=-2/3. or x-1/2, x 2/3\r
\n" ); document.write( "\n" ); document.write( "I am not sure about this one. Any help would be greatly appreciated. Thank you for your time and for your help.
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Algebra.Com's Answer #157037 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To find the vertical asymptotes, simply set the denominator equal to zero to get \"6x%5E2-x-2=0\". From there, solve for 'x' to find the x values that make the denominator equal to zero. These x values will be the equations of the vertical asymptotes.\r
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\n" ); document.write( "\n" ); document.write( "If you don't know how to solve, then....\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2-x-2=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"6x%5E2-x-2\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=6\", \"B=-1\", and \"C=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%286%29%28-2%29+%29%29%2F%282%286%29%29\" Plug in \"A=6\", \"B=-1\", and \"C=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%286%29%28-2%29+%29%29%2F%282%286%29%29\" Negate \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1-4%286%29%28-2%29+%29%29%2F%282%286%29%29\" Square \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1--48+%29%29%2F%282%286%29%29\" Multiply \"4%286%29%28-2%29\" to get \"-48\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1%2B48+%29%29%2F%282%286%29%29\" Rewrite \"sqrt%281--48%29\" as \"sqrt%281%2B48%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+49+%29%29%2F%282%286%29%29\" Add \"1\" to \"48\" to get \"49\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+49+%29%29%2F%2812%29\" Multiply \"2\" and \"6\" to get \"12\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+7%29%2F%2812%29\" Take the square root of \"49\" to get \"7\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B+7%29%2F%2812%29\" or \"x+=+%281+-+7%29%2F%2812%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%288%29%2F%2812%29\" or \"x+=++%28-6%29%2F%2812%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+2%2F3\" or \"x+=+-1%2F2\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+2%2F3\" or \"x+=+-1%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "This means that the vertical asymptotes of \"f%28x%29=%283x%2B5%29%2F%286x%5E2-x-2%29\" are \"x+=+2%2F3\" and \"x+=+-1%2F2\"
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