document.write( "Question 207501: 1. Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100mph. train B is traveling at 125mph. Train A passes a station at 4:20 p.m. If train B passes the same station at 4:32 p.m., what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #156923 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100mph. train B is traveling at 125mph. Train A passes a station at 4:20 p.m. If train B passes the same station at 4:32 p.m., what time will train B catch up to train A?
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\n" ); document.write( "from the given information, we know that train B is 12 min (.2 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: .2 * 125 = 25 mi
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\n" ); document.write( "Let t = time required for train B to catch train A
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 25 mi
\n" ); document.write( "125t = 100t + 25
\n" ); document.write( "125t - 100t = 25
\n" ); document.write( "25t = \"25%2F25\"
\n" ); document.write( "t = 1 hr
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\n" ); document.write( "4:20 + 1:00 = 5:20 pm, B catches A
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\n" ); document.write( "Check solution by finding the distances (train B travels 25 mi more than train A)
\n" ); document.write( "125 * 1 = 125 mi
\n" ); document.write( "100 * 1 = 100 mi
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\n" ); document.write( "difference = 25 mi
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