document.write( "Question 28767: The perimeter of a rectangle is 91 feet and the length is 8 feet more than twice the width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #15687 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! width = x \n" ); document.write( "Length = 2x+8 \n" ); document.write( "Formula: 2(l+w)=P\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(2x+8+x)=91 \n" ); document.write( "6x+16=91 \n" ); document.write( "6x=75 \n" ); document.write( "x=12.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(12.5)+8=33\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the width is 12.5ft and the length is 33ft. \n" ); document.write( "Paul. \n" ); document.write( " |