document.write( "Question 207423: Hi there... i just have a few questions that i would like to ask regarding complex numbers.\r
\n" ); document.write( "\n" ); document.write( "1)\"1-sqrt%283%29%2Ai\"
\n" ); document.write( "i would show you how much i can do on this one... however, im completely stuck sorry
\n" ); document.write( "and i was unable to find a proper square root sign, so hope that its alright.\r
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\n" ); document.write( "\n" ); document.write( "2)\"c+=+sqrt%282%29-i%2Asqrt%282%29\"\r
\n" ); document.write( "\n" ); document.write( "I REALLY strggle with De Moivre's theorem.
\n" ); document.write( "for this question i have to find the following:
\n" ); document.write( "a)\"abs%28c%29\"
\n" ); document.write( "b)find \"arg%28c%29\" when \"-pi%3Carg%28c%29%3Cpi\"
\n" ); document.write( "c)write \"c\" in polar form
\n" ); document.write( "d}find \"c%5E6\" or \"%28sqrt%282%29+-+i%2Asqrt%282%29%29%5E6\" using De Moivre's theorem.\r
\n" ); document.write( "\n" ); document.write( "SO those are all my questions, hope they are alright\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "Christelle :D
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Algebra.Com's Answer #156866 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I'll just do (2) and you can use it as a model to\r\n" );
document.write( "do (1). \r\n" );
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document.write( "\"c+=+sqrt%282%29-i%2Asqrt%282%29\"\r\n" );
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document.write( "Let's draw the picture of that complex number as a\r\n" );
document.write( "right triangle on a graph. \"c+=+x%2Biy=sqrt%282%29-i%2Asqrt%282%29\"\r\n" );
document.write( "where \"x=sqrt%282%29\", \"y=-sqrt%282%29\"\r\n" );
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\n" ); document.write( "(a) \"abs%28c%29\".
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document.write( "Sometimes this is called the \"modulus\". This is the length of \r\n" );
document.write( "the hypotenuse of that right triangle. We find it the same way \r\n" );
document.write( "we always find the hypotenuse, the Pythagorean theorem:\r\n" );
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document.write( "We label the hypotenuse \"r=2\" and this is the same as \"abs%28c%29\"\r\n" );
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\n" ); document.write( "(b) find \"arg%28c%29\" when \"-pi%3Carg%28c%29%3Cpi\"
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document.write( "\"Argument\" means \"angle\" (you can remember it because \"argument\"\r\n" );
document.write( "and \"angle\" both start with \"a\" and their third letters are \"g\")\r\n" );
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document.write( "Now since we are told that the argument \"phi\" is between \"-pi\"\r\n" );
document.write( "and \"%22%22%2Bpi\", we must take the argument as a negative angle \r\n" );
document.write( "measured by rotating clockwise from the right side of the x-axis, \r\n" );
document.write( "indicated by the blue arc below labeled \"phi\", \"phi\".\r\n" );
document.write( "It should be q, \"theta\", but I can't \r\n" );
document.write( "get that Greek letter on the notation program for this site, so \r\n" );
document.write( "I'll use \"phi\" instead.\r\n" );
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document.write( "Since the triangle is an isosceles right triangle, its interior\r\n" );
document.write( "angles are \"45%B0\" or \"pi%2F4\" in radians.  However since \"-pi%3Carg%28c%29%3Cpi\"\r\n" );
document.write( "tells us that the rotation is clockwise from the right\r\n" );
document.write( "side of the x-axis, the angle is taken as negative. Thus we\r\n" );
document.write( "take it as \"phi=-pi%2F4\" and we label it:\r\n" );
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\n" ); document.write( "(c) write in polar form:
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document.write( "Since \"cos%28phi%29=x%2Fr\", therefore \"x=r%2Acos%28phi%29\"\r\n" );
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document.write( "and since \"sin%28phi%29=y%2Fr\", therefore \"y=r%2Asin%28phi%29\"\r\n" );
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document.write( "So \"x%2Biy=r%2Acos%28phi%29%2Bi%2Ar%2Asin%28phi%29\"\r\n" );
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document.write( "and we can factor out \"r\" and get:\r\n" );
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document.write( "\"x%2Biy=r%28cos%28phi%29%2Bi%2Asin%28phi%29%29\"\r\n" );
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document.write( "This is the polar form \"r%28cos%28phi%29%2Bi%2Asin%28phi%29%29\" of \"x%2Biy\"\r\n" );
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document.write( "Therefore since \"r=2\" and \"phi=-pi%2F4\"\r\n" );
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document.write( "\"c+=+sqrt%282%29-i%2Asqrt%282%29=2%28cos%28-pi%2F4%29%2Bi%2Asin%28-pi%2F4%29%29\"\r\n" );
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\n" ); document.write( "(d) \"c%5E6\" or (sqrt(2)-i*sqrt(2))^6}}}
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document.write( "DeMoivre's theorem says:\r\n" );
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document.write( "Therefore:\r\n" );
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document.write( "Since \"-3pi%2F2\" is coterminal with \"pi%2F2\", we have\r\n" );
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document.write( "\"c%5E6=64%28cos%28pi%2F2%29%2Bi%2Asin%28pi%2F2%29%29=64%280%2Bi%2A1%29=+64%28i%29+=+64i\"\r\n" );
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document.write( "Edwin
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