document.write( "Question 207437This question is from textbook algebra 1 an integrated approach
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Algebra.Com's Answer #156854 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%28x%2B5%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29-3%29%28highlight%28x%29%2B5%29\" Multiply the First terms:\"%28x%29%2A%28x%29=x%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29-3%29%28x%2Bhighlight%285%29%29\" Multiply the Outer terms:\"%28x%29%2A%285%29=5%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%28-3%29%29%28highlight%28x%29%2B5%29\" Multiply the Inner terms:\"%28-3%29%2A%28x%29=-3%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%28-3%29%29%28x%2Bhighlight%285%29%29\" Multiply the Last terms:\"%28-3%29%2A%285%29=-15\".\r
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\n" ); document.write( "\n" ); document.write( "So we have the terms: \"x%5E2\", \"5%2Ax\", \"-3%2Ax\", and \"-15\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B5%2Ax-3%2Ax-15\" Now add every term listed above to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2%2Ax-15\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"%28x-3%29%28x%2B5%29\" FOILs to \"x%5E2%2B2%2Ax-15\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28x-3%29%28x%2B5%29=x%5E2%2B2%2Ax-15\".
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