document.write( "Question 207393This question is from textbook Elementary and Intermediate Algebra
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document.write( ": Raffaele ran 8 miles and then walked 6 miles. If he ran 5 mph faster than he walked and the total time was 2 hours, then how fast did he walk? \n" );
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Algebra.Com's Answer #156846 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Raffaele ran 8 miles and then walked 6 miles. If he ran 5 mph faster than he walked and the total time was 2 hours, then how fast did he walk?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let Raffaele's walking rate of speed be S\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then his running rate of speed is S + 5 (he ran 5 mph faster than he walked)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since he ran 8 miles, walked 6 miles, and did them in 2 hours, then\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8(S) + 6(S + 5) = 2(S)(S + 5) [Multiplying equation by LCD, S(S + 5)]\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(S - 5)(S + 3) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 5, or - 3 (Eliminate S = -3, as rate of speed CANNOT be negative)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, Raffaele's walking rate of speed = \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |