document.write( "Question 207370This question is from textbook precalculus
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document.write( ": how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid? \n" );
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Algebra.Com's Answer #156793 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid? \n" ); document.write( "-------------- \n" ); document.write( "The acid is 40% of 20 ounces = 8 ounces. \n" ); document.write( "0.4*20 = 8 \n" ); document.write( "---------- \n" ); document.write( "That same 8 ounces is to be 30%. The water will be the other 70%. \n" ); document.write( "8/30 = x/100 \n" ); document.write( "30x = 800 \n" ); document.write( "x = 80/3, the total amount of the solution. \n" ); document.write( "We started with 20, so 80/3 - 20 = 20/3 \n" ); document.write( "20/3 ounces of water is added. \n" ); document.write( " |