document.write( "Question 207356This question is from textbook
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Algebra.Com's Answer #156789 by Edwin McCravy(20059)\"\" \"About 
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0.10, 1.25, 1.50, 1.50, 1.75, 2.00, 2.00, 2.00, 2.00, 2.00
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document.write( "The MEAN is the ordinary AVERAGE that you learned in \r\n" );
document.write( "elementary school.\r\n" );
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document.write( "The MEDIAN with an odd number of numbers = the middle \r\n" );
document.write( "number when numbers are arranged smallest to largest \r\n" );
document.write( "or largest to smallest.\r\n" );
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document.write( "The MEDIAN with an even number of numbers = the average \r\n" );
document.write( "of the two middle numbers when numbers are arranged \r\n" );
document.write( "smallest to largest or largest to smallest.\r\n" );
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document.write( "There are 10 numbers, and 10 is even, so we use the \r\n" );
document.write( "second rule and average the two numbers in the middle \r\n" );
document.write( "which are 1.75 and 2.00.\r\n" );
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document.write( "\"MEDIAN+=+%281.75%2B2.00%29%2F2+=+3.75%2F2+=+1.875\"\r\n" );
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document.write( "Think of the fact that the MEDIAN of a highway is right in the middle.\r\n" );
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document.write( "The MODE is the number which occurs the MOST number of times.\r\n" );
document.write( "(Remember that by the fact that \"MODE\" and \"MOST\" both begin with\r\n" );
document.write( "an \"MO\" and have 4 letters.\r\n" );
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document.write( "2.00 occurs the MOST number of times so \r\n" );
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document.write( "\"MODE+=+2.00\"\r\n" );
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document.write( "The RANGE = Largest Data Value - Smallest Data Value\r\n" );
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document.write( "So \r\n" );
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document.write( "\"RANGE+=+2.00+-+0.10+=+1.90\"\r\n" );
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document.write( "So the MODE is the largest price with $2.00\r\n" );
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document.write( "Edwin

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