document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=207268>Question 207268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey, thankyou for the help..The question is_<BR>\n" );
document.write( "a open carboard measures a base of 3m x 1m and has a height of 3m. a spider in <BR>\n" );
document.write( "corner A moves across the surface of box to point  B. Wnat is teh SHORTEST distance that the spider cab travell between A and B. Imagine 3-D cube i.e. like normall room. Sorry for the ammuture drawing was limited.<BR>\n" );
document.write( "      _____________*A         <BR>\n" );
document.write( "     /            /<BR>\n" );
document.write( "    /            /<BR>\n" );
document.write( "   /____________/<BR>\n" );
document.write( "                \r<BR>\n" );
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document.write( "             3m    /<BR>\n" );
document.write( "                  / 1m<BR>\n" );
document.write( "    _____________/<BR>\n" );
document.write( "   *B    3m </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #156727 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=156727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The shortest distance between two points is a straight line and in this case, it's the diagonal that runs from corner to corner. I'm assuming that the spider is traveling from an upper corner to a bottom corner (or vice versa).\r<BR>\n" );
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document.write( "It turns out that the diagonal 'd' can be found by the formula \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2%2Bc%5E2=d%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2%2Bc%5E2=d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where 'a', 'b', and 'c' are the lengths of the box.\r<BR>\n" );
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document.write( "Note: this is analogous to the Pythagorean Theorem.\r<BR>\n" );
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document.write( "So in this case, a=3, b=1, and c=3 giving us the equation \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E2%2B1%5E2%2B3%5E2=d%5E2 ALIGN=MIDDLE  ALT=\"3%5E2%2B1%5E2%2B3%5E2=d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9%2B1%2B9=d%5E2 ALIGN=MIDDLE  ALT=\"9%2B1%2B9=d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square each value\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=19=d%5E2 ALIGN=MIDDLE  ALT=\"19=d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%2819%29 ALIGN=MIDDLE  ALT=\"d=sqrt%2819%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides. Note: we're only considering the positive square root.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=4.359 ALIGN=MIDDLE  ALT=\"d=4.359\"   DISABLED_style= \"max-width:90%; height:auto;\" > Approximate the square root.\r<BR>\n" );
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document.write( "So the shortest distance that the spider can travel from A to B is roughly 4.359 meters. </SPAN>\n" );
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