document.write( "Question 207261: question is: solve the quadratic equation by completing the square:\r
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document.write( "x^2+6x=0\r
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document.write( "x^2+6x(6/2)^2 = (6/2)^2
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document.write( "(sqrt x + sqrt 3^2)^2 = sqrt 9
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document.write( "x+3= +- 3
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document.write( "x+3=3 x+3=-3
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document.write( "x=0 x=-6\r
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document.write( "This question is not from a textbook, I would like to know if I did the work correctly, thank you so much for your help. \n" );
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Algebra.Com's Answer #156705 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! x^2 +6x =0 \n" ); document.write( ". \n" ); document.write( "complete square by using (6/2)^2 as 3rd term,,,however must add to both sides to maintain balance. \n" ); document.write( ". \n" ); document.write( "x^2 +6x +(6/2)^2 = (6/2)^2 \n" ); document.write( ". \n" ); document.write( "x^2 +6x +9 = 9 \n" ); document.write( ". \n" ); document.write( "(x+3)^2 = 9 \n" ); document.write( ". \n" ); document.write( "take square root of both sides \n" ); document.write( ". \n" ); document.write( "+/-(x+3) = +/-(3) \n" ); document.write( ". \n" ); document.write( "+ x+3 =+3,,,x=0,,,,check,,(0)^2 +6(0)=0,,,ok \n" ); document.write( ". \n" ); document.write( "-x-3 = -3,,,x=0,,,check,,ok \n" ); document.write( ". \n" ); document.write( "x+3=-3,,,x=-6,,check (-6)^2 +6(-6)=0,,,36-36=0,,,ok \n" ); document.write( ". \n" ); document.write( "-x-3=+3,,,,x=-6,,,,check,,,ok \n" ); document.write( ". \n" ); document.write( "Therefore,,,x=0,-6 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |