document.write( "Question 28712: Find the value or values of p in the quadratic equation p^2+13p-30=0 \n" ); document.write( "
Algebra.Com's Answer #15670 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! Find the value or values of p in the quadratic equation p^2+13p-30=0\r \n" ); document.write( "\n" ); document.write( "p^2+13p-30=0 ----(1) \n" ); document.write( "p^2 + [(15)p+(-2)p] - 30 =0 \n" ); document.write( "(splitting the middle term as the sum of two terms in such a way that these two when multiplied(of course along with the signs)should give the product of the square term and the constant term.) \n" ); document.write( "That is [13p =(15)p+(-2)p] and (15p)X(-2p) = -30p^2= (p^2)X(-30)] \n" ); document.write( "p^2 + 15p-2p -30= 0 \n" ); document.write( "p(p+15)-2(p+15)=0 \n" ); document.write( "pt-2t=0 where t= p+15 \n" ); document.write( "t(p-2)=0 \n" ); document.write( "(p+15)(p-2)=0 \n" ); document.write( "(p+15) = 0 gives p= -15 \n" ); document.write( "(p-2)=0 gives p= 2 \n" ); document.write( "Answer: p= -15 and p =2 \n" ); document.write( "Verification: p= -15 in p^2+13p-30=0 ----(1) \n" ); document.write( "LHS=(-15)^2 +13X(-15)-30 = 225-195-30=0 =RHs \n" ); document.write( "And p= 2 in p^2+13p-30=0 ----(1) \n" ); document.write( "LHS=(2)^2 +13X(2)-30 = 4+26-30= 0 =RHs \n" ); document.write( "Therefore our values are correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |