document.write( "Question 28714: Diophantus, the father of algebra, told this when ask his age. My youth lasted one-sixth of my life. I grew a beard after one-twelfth more. After another one-seventh, I married. Five years later I had a son. My son lived half as long as i did and then i died 4 years after my son. How old was i when i died? \r
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document.write( "I think the Variavles at death and 2x+4 at is father age at death but i cant setup the equation to solve. \n" );
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Algebra.Com's Answer #15669 by wuwei96815(245) ![]() You can put this solution on YOUR website! Let x = Diophantus' age.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1/6x + 1/12x +1/7x +1/2x + 5 + 4 = x \n" ); document.write( "9 = -1/6x -1/12x -1/7x -1/2x + x \n" ); document.write( "9 = 9/84x \n" ); document.write( "756 = 9x \n" ); document.write( "84 = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope that is right? \n" ); document.write( " \n" ); document.write( " |