document.write( "Question 28714: Diophantus, the father of algebra, told this when ask his age. My youth lasted one-sixth of my life. I grew a beard after one-twelfth more. After another one-seventh, I married. Five years later I had a son. My son lived half as long as i did and then i died 4 years after my son. How old was i when i died? \r
\n" ); document.write( "\n" ); document.write( "I think the Variavles at death and 2x+4 at is father age at death but i cant setup the equation to solve.
\n" ); document.write( "

Algebra.Com's Answer #15669 by wuwei96815(245)\"\" \"About 
You can put this solution on YOUR website!
Let x = Diophantus' age.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1/6x + 1/12x +1/7x +1/2x + 5 + 4 = x
\n" ); document.write( "9 = -1/6x -1/12x -1/7x -1/2x + x
\n" ); document.write( "9 = 9/84x
\n" ); document.write( "756 = 9x
\n" ); document.write( "84 = x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I hope that is right?
\n" ); document.write( "
\n" ); document.write( "
\n" );