document.write( "Question 207229: write a linear equation that goes through the point(3,-8) and has a slope of 1/2 \n" ); document.write( "
Algebra.Com's Answer #156675 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"1%2F2\" which goes through the point (3,-8), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y--8=%281%2F2%29%28x-3%29\" Plug in \"m=1%2F2\", \"x%5B1%5D=3\", and \"y%5B1%5D=-8\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B8=%281%2F2%29%28x-3%29\" Rewrite \"y--8\" as \"y%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B8=%281%2F2%29x%2B%281%2F2%29%28-3%29\" Distribute \"1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B8=%281%2F2%29x-3%2F2\" Multiply \"1%2F2\" and \"-3\" to get \"-3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x-3%2F2-8\" Subtract 8 from both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x-19%2F2\" Combine like terms \"-3%2F2\" and \"-8\" to get \"-19%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"1%2F2\" which goes through the point (3,-8) is \"y=%281%2F2%29x-19%2F2\"
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