document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28644>Question 28644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find all the negative odd intergers that satisfy the following inequality<BR>\n" );
document.write( "-3x+1 _<_ 17 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15667 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem I have already worked out  under someother number.<BR>\n" );
document.write( "Please verify. <BR>\n" );
document.write( "Anyway here is the answer<BR>\n" );
document.write( "Find all negative odd integers that satisfy the following inequality<BR>\n" );
document.write( "-3x+1=<17 ----(1)<BR>\n" );
document.write( "-3x=<17-1 (adding minus 1 to both the sides)<BR>\n" );
document.write( "-3x=<16<BR>\n" );
document.write( "(-3)x/(-3)>= 16/(-3)(multiplication or division by a negative quantity alters the inequality)<BR>\n" );
document.write( "x>= (-16/3)which means x is to the right of -5 and (1/3)<BR>\n" );
document.write( "and given that x is a negative odd integer.<BR>\n" );
document.write( "Therefore our set is {-5,-3,-1} </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );