document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=207194>Question 207194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> it takes you 8 hours to dig a hole, you and your brother dig a same size hole and it takes you 5 hours, how long will it take your brother to dig that same hole? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #156642 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=156642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  it takes you 8 hours to dig a hole, you and your brother dig a same size hole and it takes you 5 hours, how long will it take your brother to dig that same hole?<BR>\n" );
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document.write( "This type of problem required the sum of reciprocals approach.<BR>\n" );
document.write( "I dig 1/8 of the hole per hour.<BR>\n" );
document.write( "Bro digs 1/5 of the hole per hour.<BR>\n" );
document.write( "Now you can add those.<BR>\n" );
document.write( "Together, we dig 1/8 + 1/5 per hour<BR>\n" );
document.write( "= 13/40 of the hole per hour.<BR>\n" );
document.write( "--> 40/13 hours to dig the hole<BR>\n" );
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document.write( "There's a shortcut, which is handy on a timed test, product/sum.<BR>\n" );
document.write( "5*8/(5+8) = 40/13<BR>\n" );
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