document.write( "Question 207191: Suppose that $2000 is invested at a rate of 6% per year compounded continuously. What is the balance after 1 year? After 2 years?
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Algebra.Com's Answer #156637 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! A=Pe^rt \n" ); document.write( "A=2000(2.718)^.06(1) \n" ); document.write( "A=2000(1.06183) \n" ); document.write( "A=$2123.66 \n" ); document.write( "-------------------- \n" ); document.write( "A=2000(2.718)^.06(2) \n" ); document.write( "A=2000(2.718)^.12 \n" ); document.write( "A=2000(1.12748) \n" ); document.write( "A=$2254.96 \n" ); document.write( " |