document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28602>Question 28602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here's another one.  I am not sure but I think that there may be no solutiuon to this. <BR>\n" );
document.write( "x -y + z = -3<BR>\n" );
document.write( "x + y + z = 3<BR>\n" );
document.write( "x + y -z = 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15659 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let matrix = A\r<BR>\n" );
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document.write( "detA = 1(-1-1)--1(-1-1)+1(1-1)<BR>\n" );
document.write( "detA = -4\r<BR>\n" );
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document.write( "Now, sub the -3 3 7 column for the x-values, and recalc the det of that --> -8<BR>\n" );
document.write( "so x = -8/-4 --> 2\r<BR>\n" );
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document.write( "Now, sub the -3 3 7 column for the y-values, and recalc the det of that --> -12<BR>\n" );
document.write( "so y = -12/-4 --> 3\r<BR>\n" );
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document.write( "Now, sub the -3 3 7 column for the z-values, and recalc the det of that --> 8<BR>\n" );
document.write( "so z = 8/-4 --> -2\r<BR>\n" );
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document.write( "--> this is Cramer's Rule.\r<BR>\n" );
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document.write( "jon. </SPAN>\n" );
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