document.write( "Question 207109This question is from textbook Algeba I: An Incremental Development
\n" ); document.write( ": PLEASE HELP ME WITH THE ANSWER TO THIS WORD PROBLEM:\r
\n" ); document.write( "\n" ); document.write( "Jordan drove to town at 50 mph and rove back home at 40 mph. What is the distance to town if the whole trip took 9 hours?\r
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Algebra.Com's Answer #156576 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
going = 50 mph.
\n" ); document.write( "coming back = 40 mph.
\n" ); document.write( "total time = 9 hours
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\n" ); document.write( "RT=D
\n" ); document.write( "R = rate = miles per hour.
\n" ); document.write( "T = time = hours.
\n" ); document.write( "D = distance = miles.
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\n" ); document.write( "let x = time it took to go
\n" ); document.write( "let y = time it took to come back
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\n" ); document.write( "50*x = D
\n" ); document.write( "40*y = D
\n" ); document.write( "x + y = T
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\n" ); document.write( "since going and coming back equal the same distance, then RT going and RT coming back are equal to each other.
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\n" ); document.write( "50*x = 40*y
\n" ); document.write( "x = 40*y/50
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\n" ); document.write( "equation of x + y = T becomes:
\n" ); document.write( "40*y/50 + y = T which becomes:
\n" ); document.write( "multiply both sides of this equation by 50 to get:
\n" ); document.write( "40*y + 50*y = 50*T which becomes:
\n" ); document.write( "y*(40+50) = 50*T which becomes:
\n" ); document.write( "90*y = 50*T
\n" ); document.write( "divide both sides of this equation by 90 to get:
\n" ); document.write( "y = (50/90)*T which becomes:
\n" ); document.write( "y = (5/9)*9 = 5
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\n" ); document.write( "y = 5 hours means that x must = 4 hours because x + y = 9
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\n" ); document.write( "50 * (4) = 200 miles = D
\n" ); document.write( "40 * (5) = 200 miles = D
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\n" ); document.write( "numbers check out.
\n" ); document.write( "4 hours + 5 hours = 9 hours for the round trip.
\n" ); document.write( "distance to town is 200 miles.
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