document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=207092>Question 207092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> translate to a algebratic equation then solve.\r<BR>\n" );
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document.write( "the perimeter of a rectangular carpet is 70 feet. the width is three-fourths the lenght. find the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #156572 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=156572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2(Length + Width)<BR>\n" );
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document.write( "but  per = 70,,and  W=3/4 L,,,,,substituting<BR>\n" );
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document.write( "70 = 2(L + .75 L)=2(1.75L) = 3.5L<BR>\n" );
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document.write( "or  L= 20,,,,,,W=.75*20=15,,,,feet<BR>\n" );
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document.write( "check,, p=2(L+W) =2(20+15)=2*35=70,,,,,ok<BR>\n" );
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