document.write( "Question 28598: Im totally stumped.
\n" ); document.write( "Find the value of k that makes the linear expression a factor of a cubic expression.
\n" ); document.write( "kx^3-2x^2+x-6;x+3
\n" ); document.write( "could you show the steps or explain how?
\n" ); document.write( "Thanks \n" ); document.write( "
Algebra.Com's Answer #15657 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
for x+3 to be a factor, then putting x=-3 into the original, will give an answer of zero.\r
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\n" ); document.write( "\n" ); document.write( "so \"kx%5E3-2x%5E2%2Bx-6\" becomes
\n" ); document.write( "\"+k%28-3%29%5E3-2%28-3%29%5E2%2B%28-3%29-6+=+0+\"
\n" ); document.write( "k(-27)-2(9)+(-3)-6 = 0
\n" ); document.write( "-27k - 18 - 3 - 6 = 0
\n" ); document.write( "-27k - 27 = 0
\n" ); document.write( "-27k = 27
\n" ); document.write( "--> k = 27/-27
\n" ); document.write( "--> k = -1\r
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\n" ); document.write( "\n" ); document.write( "jon.
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