document.write( "Question 206830: I tried to solve this problem but I didnt come to far, could someone help me with it?
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document.write( "Problem; Given that the equation of a circle is x^2+y^2-10x+4y+13=0,find íts center and its radius.
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document.write( "The way I tried to solve it;
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document.write( "(x-h)^2+(y-k)^2=r^2
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document.write( "(x^2-10x+9)+(y^2+4y+1)= -13+9+1
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document.write( "(I think I did something totally wrong here) \n" );
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Algebra.Com's Answer #156356 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! you need to COMPLETE THE SQUARE for the x's and y's\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you're on the right track, but you need different constant terms\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first order terms (-10x and 4y) determine the constants\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 10x + 25 = (x - 5)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y^2 +4y + 4 = (y + 2)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 - 10x + 25) + (y^2 + 4y + 4) = -13 + 25 + 4 = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 5)^2 + (y + 2)^2 = 4^2 \n" ); document.write( " |