document.write( "Question 206812: Please help me solve this problem: (Mixture Problem)\r
\n" ); document.write( "\n" ); document.write( "1. A producer of packaged frozen meat wants to market mixed meat at P115.00 per kilogram. How many kilograms of pork meat worth P120.00 per kilogram must be mixed with 20 kilograms of chicken meat worth P100.00 per kilogram and 5 kilograms of beef meat worth P160.00 per kilogram to produce a satisfactory mixture? \n" ); document.write( "
Algebra.Com's Answer #156341 by ankor@dixie-net.com(22740)\"\" \"About 
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A producer of packaged frozen meat wants to market mixed meat at P115.00 per kilogram.
\n" ); document.write( "How many kilograms of pork meat worth P120.00 per kilogram must be mixed with 20
\n" ); document.write( "kilograms of chicken meat worth P100.00 per kilogram and 5 kilograms of beef meat
\n" ); document.write( "worth P160.00 per kilogram to produce a satisfactory mixture?
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\n" ); document.write( "Let p = amt of pork required
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\n" ); document.write( "120p + 100(20) + 160(5) = 115(p+20+5)
\n" ); document.write( ":
\n" ); document.write( "120p + 2000 + 800 = 115(p+25)
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\n" ); document.write( "120p + 2800 = 115p + 2875
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\n" ); document.write( "120p - 115p = 2875 - 2800
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\n" ); document.write( "5p = 75
\n" ); document.write( "p = \"75%2F5\"
\n" ); document.write( "p = 15 kilo of pork required
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\n" ); document.write( "Check solution:
\n" ); document.write( "120(15) + 100(20) + 160(5) = 115(15+20+5)
\n" ); document.write( "1800 + 2000 + 800 = 115(40)
\n" ); document.write( "4600 = 4600
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