document.write( "Question 206804: Half of Henry's age added to 1/3 of Daisy's age is 11 years. Six years from now the sum of their ages will be 40 years how old is each? \n" ); document.write( "

Algebra.Com's Answer #156337 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Let h = Henry's present age
\n" ); document.write( "Let d = Daisy's present age
\n" ); document.write( ":
\n" ); document.write( "Just write an equation for what it says:
\n" ); document.write( "\"Half of Henry's age added to 1/3 of Daisy's age is 11 years.\"
\n" ); document.write( " $\"1%2F2\"$ h + $\"1%2F3\"$ d = 11
\n" ); document.write( "Multiply by 6 to get rid of the fractions, results:
\n" ); document.write( "3h + 2d = 66
\n" ); document.write( ":
\n" ); document.write( "\" Six years from now the sum of their ages will be 40 years\"
\n" ); document.write( "(h+6) + (d+6) = 40
\n" ); document.write( "h + d + 12 = 40
\n" ); document.write( "h + d = 40 - 12
\n" ); document.write( "h + d = 28
\n" ); document.write( ":
\n" ); document.write( " how old is each?
\n" ); document.write( "Multiply the above equation by 2 and subtract from the 1st equation
\n" ); document.write( "3h + 2d = 66
\n" ); document.write( "2h + 2d = 56
\n" ); document.write( "---------------subtraction eliminates d, find h
\n" ); document.write( "h = 10
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "I'll let you find d, then check the two solutions in both equations \n" ); document.write( "

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