document.write( "Question 206795: A coin is tossed 6 times. Find the probabilities of getting the following:
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Algebra.Com's Answer #156328 by Edwin McCravy(20054)\"\" \"About 
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A coin is tossed 6 times. Find the probabilities of getting the following:
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document.write( "Here is the binomial rule:\r\n" );
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document.write( "If \"p\" is the probability of getting \"1\" success in \"1\" trial,\r\n" );
document.write( "and \"n\" is the number of trials, and \"q=1-p\", then the \r\n" );
document.write( "probability of getting exactly \"r\" successes out of the \"n\" \r\n" );
document.write( "trials is\r\n" );
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document.write( "\"%28nCr%29%28p%5Er%29%28q%5E%28n-r%29%29\"\r\n" );
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document.write( "Here a success will be a head on a coin, and a trial\r\n" );
document.write( "will be a toss. Here \"p=1%2F2\" is the probability \r\n" );
document.write( "of getting \"1\" head in \"1\" trial. There are \"6\"\r\n" );
document.write( "trials (tosses), so \"n=6\". Then the probability of \r\n" );
document.write( "getting exactly \"3\" heads out of the \"6\" trials \r\n" );
document.write( "is gotten by substituting in that expression, with \r\n" );
document.write( "\"q=1-p=1=1%2F2=1%2F2\".\r\n" );
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document.write( "\"%286C3%29%281%2F2%29%5E3%281%2F2%29%5E%286-3%29\"\r\n" );
document.write( "\"%28%286%2A5%2A4%29%2F%283%2A2%2A1%29%29%281%2F2%29%5E%283%29%281%2F2%29%5E%283%29\"\r\n" );
document.write( "\"%28120%2F6%29%281%2F2%29%5E3%281%2F2%29%5E3\"\r\n" );
document.write( "\"%2820%29%281%2F8%29%281%2F8%29\"\r\n" );
document.write( "\"%2820%29%281%2F64%29\"\r\n" );
document.write( "\"5%2F16%29\"\r\n" );
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document.write( "Edwin
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