document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206800>Question 206800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-(4+-3) How do you use commutative and distributive on this expression </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #156324 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=156324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-(4+-3) = 2x-(4-3) = 2x-4+3 = 2x-1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So 2x-(4+-3) = 2x-1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Note: adding a negative is the same as subtracting. So 4+-3 is equivalent to 4-3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );