document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28701>Question 28701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -3/5[2/3-1/2(3/4-1/2)]\r<BR>\n" );
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document.write( "I have worked this equation to death and come up with -3/5 but the book says the answer is -13/40.....please help me see how they arrived at this answer.  Thanks!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15632 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3/5[2/3-1/2(3/4-1/2)]<BR>\n" );
document.write( "=-3/5[2/3-(1/2)X(3/4)+(1/2)X(1/2)]<BR>\n" );
document.write( "=-3/5[2/3-3/8+1/4]<BR>\n" );
document.write( "=-3/5[(2X8)-(3X3)+(1X6)]/24  (the lcm of 3,8 and 4 is 24 and hence  multiplying every nr and  dr of every term by 24)<BR>\n" );
document.write( "=(-3/5)X[(16-9+6)/24]<BR>\n" );
document.write( "=(-3/5)X[13/(3X8)]<BR>\n" );
document.write( "=(-13)/40  (canceling 3)(and multiplying 5 and 8 in the dr.<BR>\n" );
document.write( "Answer:(-13/40)  </SPAN>\n" );
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