document.write( "Question 206771This question is from textbook Algebra and Trigonometry with Analytic Geometry
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document.write( ": A woman begins jogging at 3:00 P.M., running due north at a 6- minute- mile pace. Later, she reverses direction and runs due south at a 7- minute mile pace. If she returns to her starting point at 3:45 P.M., find the total number of miles run.\r
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document.write( "methods tried:
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document.write( "6(3/4-t)= 7 (3/4)
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Algebra.Com's Answer #156309 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A woman begins jogging at 3:00 P.M., running due north at a 6- minute- mile pace. Later, she reverses direction and runs due south at a 7- minute mile pace. If she returns to her starting point at 3:45 P.M., find the total number of miles run. \n" ); document.write( ": \n" ); document.write( "Using mile-min we have: \n" ); document.write( ": \n" ); document.write( "Let t = time (minutes) running a 6 min-mile \n" ); document.write( "then \n" ); document.write( "(45-t) = time running a 7 min-mile \n" ); document.write( ": \n" ); document.write( "A distance equation in miles \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "7t = 6(45-t) \n" ); document.write( "7t = 270 - 6t \n" ); document.write( "7t + 6t = 270 \n" ); document.write( "t = \n" ); document.write( "t = 20.77 min at a 6 min-mile \n" ); document.write( "and \n" ); document.write( "45 - 20.77 = 24.23 min at a 7 min-mile \n" ); document.write( ": \n" ); document.write( "Find the distances, (should be equal) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------ \n" ); document.write( "total distance 6.92 mi \n" ); document.write( " |