document.write( "Question 206572: solve for the exact value of x where 0 greater than or equal to X and less than/equal to 2 pi.\r
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document.write( "cos^2 x-1=0\r
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document.write( "I did the factoring and FOILing and\r
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document.write( "The two answers I got were:\r
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document.write( "cosx=-1 cosx=1
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document.write( "x=pi x=0,2pi\r
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document.write( "According to my instructor cosx=1's answers are not completly correct. I dont see what the problem is since cos(0) and cos(2pi) both =1. Am I missing something here? Thank you for your help. \n" );
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Algebra.Com's Answer #156300 by mickclns(59)![]() ![]() ![]() You can put this solution on YOUR website! I'd be interested in seeing your instructor's answer (please email me). It seems correct to me, too. \r \n" ); document.write( "\n" ); document.write( "Things I can see: \n" ); document.write( "You say \"where 0 greater than or equal to X and less than/equal to 2 pi\" by which I assume you mean \n" ); document.write( "\n" ); document.write( "Another possibility, the span usually given in problems such as this is |