document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206759>Question 206759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and train B are traveling on parallel tracks, going in the same direction. Train A is going 60mph and train B is going 80mph. Train A passes a station at 5:15pm. If train B passes the same station as 5:27pm, what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #156290 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=156290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A and train B are traveling on parallel tracks, going in the same direction. Train A is going 60mph and train B is going 80mph. Train A passes a station at 5:15pm. If train B passes the same station as 5:27pm, what time will train B catch up to train A?<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "From 515 to 527 is 12 minutes = 0.2 hours.<BR>\n" );
document.write( "Train A will be 60mph * 0.2 hour = 12 miles ahead when Train B passes the station.<BR>\n" );
document.write( "Train B is gaining on train A at 20 mph (80-60).<BR>\n" );
document.write( "12 miles/20 mph = 0.6 hours = 36 minutes<BR>\n" );
document.write( "5:27 + 0:36 = 6:03 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );